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1.1 Functions: Language & Notation
Quick Notes & Formulae
Essential concepts for solving function problems.
Function Definition
A mapping where every input element
x
maps to exactly one output element
y
.
Domain vs Range
D
o
m
a
i
n
: Set of all possible inputs (x-values).
R
a
n
g
e
: Set of all resulting outputs (y-values), also called the image set.
One-One Function
Matches each output to exactly one input. passes the <strong>Horizontal Line Test</strong>. Required for an inverse function to exist.
Many-One Function
Multiple inputs can map to the same output (e.g.,
y
=
x
2
). Not one-one, so no inverse unless domain is restricted.
Completed Square
a
(
x
−
h
)
2
+
k
. Vertex at
(
h
,
k
)
. Useful for finding range of quadratics.
Composite Function
f
g
(
x
)
=
f
(
g
(
x
)
)
. Apply
g
first, then
f
. Domain of
f
must accept range of
g
.
Past Paper Style Questions
Question 1: Function Mapping, Domain & Range
A mapping is defined from set
A
=
{
−
2
,
−
1
,
0
,
1
,
2
,
3
}
to set
B
=
{
0
,
1
,
2
,
3
,
4
,
5
,
6
,
7
,
8
,
9
}
, with
f
:
x
↦
x
2
+
1
.
(a) Write down
f
(
−
2
)
,
f
(
0
)
,
f
(
3
)
. [2]
(b) List the
range (image set)
of
f
for the given domain
A
. [2]
(c) State whether
f
is
one–one
or
many–one
on domain
A
. Give a reason. [1]
(d) Find a
restricted domain
A
′
⊆
A
such that
f
becomes one–one. [1]
Solution
Question 2: Graph to Domain/Range & One-one Test
The graph of
y
=
f
(
x
)
consists of:
a straight line segment from
(
−
2
,
3
)
to
(
1
,
0
)
, and
a curve
y
=
(
x
−
1
)
2
for
1
≤
x
≤
4
.
(a) State the
domain
of
f
. [1]
(b) State the
range
of
f
. [2]
(c) Explain whether
f
is one–one on its domain. [1]
(d) State a domain restriction that makes
f
one–one, and write the new range. [2]
Solution
Question 3: Function Notation and Image Set
A function is defined by
f
(
x
)
=
2
x
−
3
x
+
1
.
(a) Evaluate
f
(
0
)
,
f
(
2
)
,
f
(
−
3
)
. [3]
(b) State the
domain
of
f
for real
x
. [1]
(c) By algebraic reasoning, show that
f
(
x
)
≠
2
for all real
x
in the domain. [2]
(d) Hence state the
range
of
f
. [1]
Solution
Question 4: Many-one vs One-one using Algebra
Let
f
(
x
)
=
x
2
−
4
x
+
1
for
x
∈
R
.
(a) Write
f
(
x
)
in completed square form. [2]
(b) Find the minimum value of
f
(
x
)
. [1]
(c) Hence state the
range
of
f
. [1]
(d) Explain why
f
is
many–one
. [1]
(e) State a restricted domain that makes
f
one–one. [1]
Solution
Question 5: Mapping Diagram Interpretation
A mapping diagram
(
domain
→
codomain
)
shows:
1
↦
4
2
↦
4
3
↦
5
4
↦
7
5
↦
7
(a) Is this relation a
function
? Give a reason. [1]
(b) State whether it is
one–one
or
many–one
. [1]
(c) Write the domain and the range. [2]
(d) One value in the domain is removed so the mapping becomes one–one. State one possible value removed and justify briefly. [2]
Solution
Question 6: Piecewise Function
A function
f
is defined by:
f
(
x
)
=
{
3
−
x
,
−
1
≤
x
<
2
x
−
2
,
2
≤
x
≤
6
(a) State the
domain
of
f
. [1]
(b) Find the
range
of
f
. [2]
(c) Determine whether
f
is one–one on its domain. [1]
(d) Find a domain restriction so that
f
becomes one–one. [1]
Solution
Question 7: Logarithmic Function
The function
f
is given by
f
(
x
)
=
ln
(
x
−
1
)
+
2
.
(a) State the domain of
f
. [1]
(b) State the range of
f
. [1]
(c) Sketch the graph of
y
=
f
(
x
)
, showing asymptotes. [2]
(d) Explain whether
f
is one–one. [1]
Solution
Question 8: Function Test
Consider the curve
x
=
y
2
−
2
y
.
(a) Explain why this relation does
not
define y as a function of x over reals. [1]
(b) Rearrange to express y in terms of x. [2]
(c) State a restriction on y so that y becomes a function of x. [1]
Solution
Question 9: Modulus Function
Let
f
(
x
)
=
|
2
x
−
5
|
for
−
1
≤
x
≤
6
.
(a) Find
f
(
−
1
)
,
f
(
2.5
)
,
f
(
6
)
. [2]
(b) State the domain and range. [2]
(c) Is
f
one–one on
[
−
1
,
6
]
? Explain. [1]
(d) Give a restricted domain interval where
f
is one–one. [1]
Solution
Question 10: Transformed Graph
Basic graph
y
=
x
is transformed to
f
(
x
)
=
3
−
2
x
+
1
.
(a) State the domain of
f
. [1]
(b) State the range of
f
. [2]
(c) Find coordinates where
x
=
−
1
. [1]
(d) Is
f
one–one? [1]
Solution