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1.1 Quadratic Factorisation Worksheet
Quick Notes & Formulae
Essential rules for quadratic manipulation.
Trinomial Pattern
x
2
+
(
p
+
q
)
x
+
p
q
=
(
x
+
p
)
(
x
+
q
)
AC Method (a ≠ 1)
Find
p
,
q
such that
p
⋅
q
=
a
c
and
p
+
q
=
b
. Split
b
x
.
Quadratic Formula
x
=
−
b
±
b
2
−
4
a
c
2
a
Difference of Squares
a
2
−
b
2
=
(
a
−
b
)
(
a
+
b
)
Vertex Form
y
=
a
(
x
+
p
)
2
+
q
Turning point at
(
−
p
,
q
)
.
Completing Square
x
2
+
b
x
=
(
x
+
b
2
)
2
−
(
b
2
)
2
Past Paper Style Questions
Question 1: Completing the Square [9709/13/M/J/15]
Express
2
x
2
−
12
x
+
7
in the form
a
(
x
+
b
)
2
+
c
, where
a
,
b
and
c
are constants. [3]
Solution
Question 2: Factorisation with a ≠ 1
Factorise correctly:
3
x
2
+
13
x
−
10
.
Solution
Question 3: Common Factor First
Factorise completely:
2
x
2
+
16
x
+
30
.
Solution
Question 4: Difference of Two Squares
Factorise
49
x
2
−
64
.
Solution
Question 5: DOTS with Coefficients
Factorise
20
x
2
−
45
.
Solution
Question 6: Solving with Quadratic Formula
Solve the equation
2
x
2
−
5
x
+
1
=
0
, giving your answers in exact surd form.
Solution
Question 7: Completing the Square (a=1)
Express
x
2
+
8
x
+
3
in the form
(
x
+
a
)
2
+
b
.
Solution
Question 8: Completing the Square (a≠1)
Express
2
x
2
−
12
x
+
7
in the form
a
(
x
+
p
)
2
+
q
.
Solution
Question 9: Turning Points
A quadratic curve has the equation
y
=
−
x
2
+
4
x
+
5
.
1. Express the equation in form
a
−
(
x
+
b
)
2
.
2. State the coordinates of the turning point.
Solution
Question 10: Graphing & Intercepts
Find the coordinates of the intercepts with the axes for the curve
y
=
x
2
−
4
x
−
12
.
Solution
Question 11: Sketching a Quadratic (a < 0)
Sketch the graph of
y
=
3
+
2
x
−
x
2
. Show technical details including the
y
-intercept,
x
-intercepts, and the coordinates of the turning point.
Solution
Question 12: Finding the Equation from Features
A quadratic curve has its maximum turning point at
(
2
,
9
)
and passed through the point
(
0
,
5
)
. Find the equation of the curve in the form
y
=
a
x
2
+
b
x
+
c
.
Solution
Question 13: Algebraic Fractions
Solve the following equations:
a)
4
x
+
1
+
3
x
−
1
=
2
b)
2
x
+
5
x
+
3
=
1
Solution
Question 14: Rational Equations (Zero Numerator)
Solve:
a)
3
x
2
+
x
−
4
x
2
−
4
=
0
b)
x
2
−
9
5
x
+
10
=
0
Solution
Question 15: Rational Equations (Zero Numerator II)
Solve:
a)
x
2
−
5
x
−
6
x
2
+
1
=
0
b)
2
x
2
+
7
x
−
4
x
2
+
x
+
4
=
0
Solution
Question 16: Rearranging to Quadratic Form
Find the real solutions:
a)
9
(
x
2
−
4
x
+
3
)
=
1
b)
4
(
2
x
2
−
x
−
5
)
=
9
Solution
Question 17: Squared Expressions
Find the real solutions:
a)
(
x
2
−
6
x
+
5
)
2
=
16
b)
(
2
x
2
−
3
x
−
2
)
2
=
25
Solution
Question 18: Geometry Application (Triangle)
A right-angled triangle has sides
(
x
+
2
)
cm,
(
2
x
+
6
)
cm and 13 cm.
a) Show that
5
x
2
+
28
x
−
129
=
0
.
b) Find the lengths of the sides.
Solution
Question 19: Geometry Application (Trapezium)
The area of a trapezium is 48 cm
2
. The parallel sides are
x
cm and
(
x
+
6
)
cm, and the height is
(
x
−
2
)
cm. Find the value of
x
.
Solution
Question 20: Exponential Hidden Quadratic
Solve
(
x
2
−
7
x
+
10
)
x
2
−
x
−
2
=
1
.
Solution